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9.3 The acidic environment 4. Definitions of acid and
base
| Syllabus reference (October 2002
version) |
|
4. Because of the prevalence and importance of acids,
they have been used and studied for hundreds of
years. Over time, the definitions of acid and base
have been refined
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Students learn to:
|
Students:
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Extract from Chemistry Stage 6 Syllabus (Amended October
2002). © Board of Studies, NSW.
[Edit: 27 Jun 08]
Background: As the properties of acids
and bases have been observed and particle concepts
developed, there has been a change in the definitions of an
acid and base. The original definitions were based on
observable properties, such as an acid tastes
sour, or an acid turns litmus red. More
recent definitions have been based on particle concepts,
such as an acid is a proton donor.
gather and
process
information from secondary sources to trace developments
in understanding and describing acid/base
reactions
- This is an opportunity for you to
gather relevant information to summarise
the developments in understanding and describing acid-base
reactions by Arrhenius and Bronsted-Lowry. The information
required is readily available in HSC chemistry level texts.
- Process the information by accessing a
number of sources. When you have identified a source of
information, evaluate its validity by checking the
reputation of the source and by looking to see how the
information compares to information from other sources. You
might use a table like that following to record and compare
information.
| Scientist(s) |
Acid definition |
Base definition |
Notes |
| Arrhenius |
? |
? |
Water solutions only |
| Bronsted-Lowry |
? |
? |
Acid must contain hydrogen |

outline
the historical development of ideas about acids including
those of:

outline
the Brönsted-Lowry theory of acids and
bases
- A theory, based on proton transfer, was independently
outlined in 1923 by the Danish chemist, Johannes Bronsted,
and the British chemist, Thomas Lowry. An acid is a proton
donor and a base is a proton acceptor.
- An acid-base reaction involves proton transfer from
acid to base.
- The Bronsted-Lowry theory is used to explain acids and
bases in Stage 6 science courses.

describe
the relationship between an acid and its conjugate base and a
base and its conjugate acid
- When an acid donates a proton, it forms its conjugate
base.
HCl
+ H2O
Cl-
+ H3O+
acid
conjugate base
- When a base accepts a proton, it forms its conjugate
acid.
HCl
+ H2O
Cl-
+ H3O+
base conjugate
acid

identify
conjugate acid/base pairs
- Whenever an acid and a base react, they form their
conjugates:
HCl
+ H2O
Cl-
+
H3O+
acid1
base2
conjugate base1 conjugate
acid2
- Hydrochloric acid and chloride ion are a conjugate
acid-base pair.
- Water and hydronium ion are another conjugate acid-base
pair.

identify
neutralisation as a proton transfer reaction which is
exothermic
-
In junior high school, neutralisation is studied as the
reaction between an acid and a base to form a salt and
water. The solutions reacted to demonstrate
neutralisation are usually of a strong acid, such as
hydrochloric acid, and a strong base, such as sodium
hydroxide.
acid
+
base
salt
+ water
HCl
+ NaOH
NaCl +
H2O
H+ + Cl- + Na+ +
OH-
Na+ + Cl-
+ H2O
- The net ionic equation for reaction is:
H+
+
OH-
H2O
- The net ionic equation shows that neutralisation is a
proton transfer reaction. A proton from the acid
transfers to the hydoxide ion of the base.
- All neutralisations are exothermic. When the heat of
neutralisation is measured for a range of strong acids and
strong bases, the amount of heat released is always about
57 kJ per mole of water formed. This is the heat change for
the following reaction:
H+ + OH-
H2O DH =
- 57 kJ mol-1

perform a
first-hand investigation and solve
problems using titrations and including the preparation
of standard solutions, and use available
evidence to quantitatively and qualitatively describe
the reaction between selected acids and bases
- There are many successful procedures readily available
to describe how to perform titrations, including how to
prepare of standard solutions. When
performing the investigation, be careful
to minimise hazards and wastage of resources. The notes
that follow the next syllabus point provide you with a
description of the issues that must be addressed.
- Use identified problem-solving
strategies to develop quantitative descriptions of the
reactions you study. Some of these are described in the
notes for the next syllabus point. You should be able to
match your quantitative descriptions to the qualitative
observations you have made.
-
When using evidence from your
titrations, propose ideas that demonstrate coherence and
logical progression and include correct use of scientific
principles and ideas.
- A titration can be carried out between a solid
water soluble acid or base and a standard solution. For
example an aspirin (acetylsalicylic acid) tablet can be
titrated against a solution of NaOH using
phenolphthalein indicator. Commercially bought tablets
have labels indicating the amount of monoprotic
acetylsalicylic acid in each tablet. Before titrating,
the aspirin tablet needs to be crushed in about 10 mL
of ethanol or methylated spirits.
-
The first step in the calculations for a
neutralisation reaction is to write out a balanced
equation for the reaction in this format:
aAcid +
bBase
salt + water
e.g. H2SO4 + 2NaOH
Na2SO4 +
2H2O
Here, a = 1 and b = 2
-
For the two solutions that have been used, the
unknown acid concentration, ca , or
unknown base concentration, cb , can be
calculated using the relationship:

where c = molar (moles per litre) concentration
and v = volume (va and vb must
be in the same units).
e.g. if 25.0 mL of 0.0124 M NaOH solution reacts
with 15.6 mL of H2SO4 solution,
the calculation is: 
ca =
= 0.00994
If one of the reactants is a solid, then convert
the mass of solid reactant in grams to
moles. Replace
cava or
cbvb with the number
of moles. In this case, the volume of the other
reactant must be in L because cv is
in moles. When c is in moles per
litre, v is in litres.
e.g. if 37.9 mL of sulfuric acid solution is
required to neutralise 1.56 g of CaCO3 ,
the calculation is:
CaCO3 + H2SO4
CaSO4 +
H2O + CO2
1.56 g CaCO3 =
= 0.0156 mole
= 0.0156
ca =
= 0.412 M
The amount of product can also be calculated
using the mole concept.
- For instance, as we can see from the previous example,
the amount of CO2 product is 0.0156 mole because
each mole of CaCO3 produces one mole of
CO2.
0.0156 mole of CO2 = 0.0156 mol x 44.0 g
mol-1 = 0.686 g
0.0156 mole of CO2 = 0.0156 x 24.8 L of gas at
100 kPa and 298 K = 0.387 L

describe
the correct technique for conducting titrations and
preparation of standard solutions

choose
equipment and perform a
first-hand investigation to identify
the pH of a range of salt solutions
- Choose the most appropriate equipment
available to you. If possible, a pH meter or data logger
with probe would be most suitable, otherwise select
indicator solution or indicator paper to measure the pH of
the salt solutions.
- To ensure you perform a valid
investigation, prepare solutions of salts of equal
concentration. Suitable salts are ammonium chloride
(NH4Cl), sodium chloride (NaCl), sodium
carbonate (Na2CO3) and potassium
acetate (KCH3COO).

identify
a range of salts which form acidic, basic or neutral
solutions and explain
their acidic, neutral or basic nature
- Salt ions formed from weak acids or weak bases can
react with water to reform the acid or base. In undergoing
these hydrolysis reactions, they release OH- or
H+, which can produce basic or acidic salt
solutions.
- Ammonium salt solutions are acidic, because
NH4+ + H2O
NH3 + H3O+
- Sodium chloride solution is neutral, because
Na+ and Cl- (ions from the strong
base NaOH and the strong acid HCl) do not undergo
hydrolysis.
- Sodium carbonate solution is basic, because the
carbonate ion from the weak acid carbonic acid can
hydrolyse.
CO32- + H2O
HCO3- +
OH-
- Similarly, potassium acetate solution is basic.
CH3COO- + H2O
CH3COOH + OH-
- If a salt is made up of two ions that hydrolyse to the
same extent, the salt solution could be close to neutral,
e.g. ammonium acetate NH4CH3COO.
NH4+ + H2O
NH3 + H3O+
CH3COO- + H2O
CH3COOH + OH-
The resulting reaction, H3O+ +
OH-
2H2O, results in a neutral
solution.

identify
amphiprotic substances and construct equations to describe
their behaviour in acidic and basic solutions

perform a
first-hand investigation to determine the concentration of a
domestic acidic substance using
computer-based technologies
- Vinegar contains acetic acid which can be titrated
against standardised NaOH(aq) using a pH probe attached to
a data logger. The data recorded can be used to draw a
graph. The endpoint is where the pH changes most rapidly.
OR
- A standard solution of NaOH cannot be prepared by
directly weighing out NaOH as the solid absorbs water and
reacts with carbon dioxide in the air. A NaOH(aq) solution
prepared in this way needs to be standardised by titration
against a suitable acid, such as oxalic acid
(COOH)2.2H2O.
For the titration use a pH probe attached to a data logger
to produce a graph that shows the endpoint where the pH
changes most rapidly.

analyse
information from secondary sources to assess the
use of neutralisation reactions as a safety measure or to
minimise damage in accidents or chemical spills
-
A substance containing an amphiprotic ion, such as the
hydrogen carbonate ion in NaHCO3, is quite
suitable for neutralising chemical spills.
If the chemical spill contains an acid, H+
+ HCO3-
H2O + CO2
If the spill contains a base,
HCO3- + OH-
CO32- +
H2O.
Thus, NaHCO3 is suitable for neutralising
chemical spills of acids, bases and unknown acidity or
basicity.
- Analyse information from secondary
sources to suggest another amphiprotic substance suitable
for neutralising a chemical spill, making sure you include
the reason for your judgement.

qualitatively describe
the effect of buffers with reference to a specific example in
a natural system
- A buffer controls the level of acidity or basicity in a
solution. If an acid or a base is added to a buffer
solution, there is hardly any change in pH.
- A buffer solution is usually a mixture of a weak acid
and its conjugate base, such as hydrogen carbonate ions,
HCO3-, and carbonate ions,
CO32-.
- If an acid is added to the buffer, the hydrogen ions
are removed by
H+ + HCO3-
H2CO3
- If a base is added to the buffer, hydroxide ions are
removed by
OH- + HCO3-
H2O +
CO32-
- The net effect is that the pH of the solution
containing buffer changes only slightly.
- Hydrogen carbonate ions are important in maintaining
the pH of human blood at about 7.4.
